Without an equality sign and not knowing the plus or minus value of 11 it can't be considered to be an equation.
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(x+11)(x-6) x^2 + 5x - 66 = 0
11 and 11. In general, you can write an equation (or two equations), and solve with the quadratic formula, to solve this type of questions.
11
The tangent to 2x3 - 3x2 - 8x + 9 at x = 2 is y = 4x - 11 The tangent to y = 2x3 - 3x2 - 8x + 9 at x = 2 has the same gradient as the curve at that point; to find the gradient, differentiate: dy/dx = 6x2 - 6x - 8 which at x = 2 is: gradient = 6 x 22 - 6 x 2 - 8 = 4 At x = 2, y = 2 x 23 - 3 x 22 - 8 x 2 + 9 = -3 The equation of a line through point (xo, yo) with gradient m is: y - yo = m(x - xo) Thus the equation of the tangent to the line at x = 2 is: y - -3 = 4(x - 2) ⇒ y = 4x - 11
the solution is the answer to the equation. A solution is any value that makes the equation true. x + 2 = 10 has exactly one solution ....x=8 x + 2 > 10 has infinitely many solutions....x=9 or 10 or 11 or 12 or 13, etc