if:
y = x2
y = x + 6
then
x2 = x + 6
=> x2 - x - 6 =0
=> (x - 3)(x + 2) = 0
=> x = 3 or -2
=> y = 9 or 4 respectively, ie the points (3, 9) and (-2, 4).
89
(-4,-6)
b = sqrt32 or 4 root 2
4
Two solutions and they are:- x = 0 and y = 3
89
The solutions to the quadratic equation are: x = -1 and x = 6
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
(-4,-6)
b = sqrt32 or 4 root 2
X squared = x+6 6+x=x squared X=6
X squared plus b squared equals c squared when x and b squared equals 5 - 2 what does c equal
4
The discriminant is 121.
x = plus or minus 6.
Two solutions and they are:- x = 0 and y = 3
The graph is a circle with a radius of 6, centered at the origin.