You can use the quadratic equation for this one. Set a = 2, b = 5, c = -k.
Another Answer:-
Using the discriminant of b^2-4ac = 0
25-4(-2k) = 0 => 25+8k = 0 => k = -25/8 or -3.125
So: 2x^2+5x-(-3.125) = 0
Using the quadratic equation formula: x has equal values of -5/4 or - 1.25
There's an equals missing...
No. It's a quadratic equation, and it has two solutions.
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
no
It is a quadratic equation and its solutions are: x = 4 or x = -9
The quadratic equation will have two solutions.
There's an equals missing...
No. It's a quadratic equation, and it has two solutions.
The solutions to the quadratic equation are: x = -1 and x = 6
2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34
If: n squared -n -90 = 0 Then the solutions are: n = 10 or n = -9
no
The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.
It is a quadratic equation and its solutions are: x = 4 or x = -9
It is a quadratic equation and its solutions are: x = -3/2 and x = 3
1st equation: x^2 -xy -y squared = -11 2nd equation: 2x+y = 1 Combining the the two equations together gives: -x^2 +3x +10 = 0 Solving the above quadratic equation: x = 5 or x = -2 Solutions by substitution: (5, -9) and (-2, 5)
If the 64 has a minus sign, then the solution is x = +/-5 Simplifying gives 4x squared = 100 ie x squared = 25...