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1st equation: x^2 -xy -y squared = -11

2nd equation: 2x+y = 1

Combining the the two equations together gives: -x^2 +3x +10 = 0

Solving the above quadratic equation: x = 5 or x = -2

Solutions by substitution: (5, -9) and (-2, 5)

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The solutions are (x, y) = (-2, 5) and (5, -9).

Q: What are the solutions of the simultaneous equations of x squared -xy -y squared equals -11 and 2x plus y equals 1?

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The solutions are: x = 4, y = 2 and x = -4, y = -2

They are: (3, 1) and (-11/5, -8/5)

These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.

They are simultaneous equations and their solutions are x = 41 and y = -58

Merge the equations together and form a quadratic equation in terms of x:- 3x2-20x+28 = 0 (3x-14)(x-2) = 0 x = 14/3 or x = 2 So when x = 14/3 then y = -13/3 and when x = 2 then y = 1

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The solutions are: x = 4, y = 2 and x = -4, y = -2

They are: (3, 1) and (-11/5, -8/5)

If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)

The two rational solutions are (0,0,0) and (1,1,1). There are no other real solutions.

These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.

Through a process of elimination and substitution the solutions are s = 8 and x = 5

They are simultaneous equations and their solutions are x = 41 and y = -58

Simultaneous suggests at least two equations.

Merge the equations together and form a quadratic equation in terms of x:- 3x2-20x+28 = 0 (3x-14)(x-2) = 0 x = 14/3 or x = 2 So when x = 14/3 then y = -13/3 and when x = 2 then y = 1

Do you mean: 4x+7y = 47 and 5x-4y = -5 Then the solutions to the simultaneous equations are: x = 3 and y = 5

Simultaneous equations.

The system is simultaneous linear equations