If: x = 2y-2 and x^2 = y^2+7
Then: (2y-2)^2 = y^2+7
So: (2y-2)(2y-2) = y^2+7
It follows: 4y^2-y^2-8y+4-7 = 0 => 3y^2-8y-3 = 0
Solving the above quadratic equation: y = -1/3 or y = 3
Solutions: when y = 3 then x = 4 and when y = -1/3 then x = -8/3
1 If: 2x+5y = 16 and -5x-2y = 2 2 Then: 2*(2x+5y =16) and 5*(-5x-2y = 2) is equvalent to the above equations 3 Thus: 4x+10y = 32 and -25x-10y = 10 4 Adding both equations: -21x = 42 or x = -2 5 Solutions by substitution: x = -2 and y = 4
Equations: 7x-8y = 9 and 11x+3y = -17 Multiply all terms in the 1st equation by 11 and all terms in the 2nd by 7 So: 77x-88y = 99 and 77x+21y = -119 Subtract the 1st equation from the 2nd equation: 109y = -218 => y = -2 Through substitution the solutions are: x = -1 and y = -2
If: 3x-5y = 16 then -5y = 16-3x => y = -3.2+0.6x by dividing all terme by -5 If: xy = 7 then x(-3.2+0.6x) = 7 => -3.2x+0.6x2 -7 = 0 Solving the quadratic equation: x = 7 or x = -5/3 Solutions of the equations by substitution are: x = 7, y = 1 and x = -5/3, y = -21/5
Eqn (A): => 2x + 5y = 16 Eqn (B): => 5x + 2y = -2 5*Eqn (A) - 2*Eqn (B): 21y = 84 => y = 4 Substituting for y in Eqn (a): x = -2
They are two types of Non-Ideal solutions. They are (i) Non-Ideal solutions showing positive deviation (ii) Non-ideal solutions showing negative deviation
If: x-2y = 1 and 3xy -y^2 = 8 Then: x = 1+2y and 3(1+2y)y -y^2 = 8 Hence: 3y+6y^2 -y^2 = 8 => 5y^2 +3y -8 = 0 Solving the above quadratic equation: y =1 or y = -8/5 Solutions by substitution are: when y=1 then x=3 and when y=-8/5 then x=-11/5
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
An equation showing all dissolved compounds as ions
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The graph of an equation represents the solution set of the equation, that is all the solutions of the equation are points that lie on the graph and all the points that lie on the graph are solutions of the equation.
An inequality and a two-step equation are similar in that both involve algebraic expressions and require solving for a variable. Each represents a relationship between quantities, with equations showing equality and inequalities showing a range of possible values (greater than, less than, etc.). Both require similar techniques, such as isolating the variable, but while equations yield a specific solution, inequalities provide a set of possible solutions. Ultimately, both are essential tools in algebra for modeling and solving problems.
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