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If: 3x-5y = 16 then -5y = 16-3x => y = -3.2+0.6x by dividing all terme by -5

If: xy = 7 then x(-3.2+0.6x) = 7 => -3.2x+0.6x2 -7 = 0

Solving the quadratic equation: x = 7 or x = -5/3

Solutions of the equations by substitution are: x = 7, y = 1 and x = -5/3, y = -21/5

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