If: 2x+y = 1 then y = 1-2x
If: x^2 -xy -y^2 = -11 then x^2 -x(1-2x) -(1-2x)^2 -11 = 0
Multiplying out the brackets: x^2 -x+2x^2 -1+4x -4x^2+11 = 0
Collecting like terms: -x^2+3x+10 = 0
Solving the above quadratic equation: x = 5 or x = -2
Solutions by substitution: when x = 5 then y = -9 and when x = -2 then y = 5
many solutions
24
This quadratic equation has no solutions because the discriminant is less than zero.
Two solutions and they are:- x = 0 and y = 3
zero solutions. If you plot these two lines, you will see that they are parallel and do not intersect.
It is a quadratic equation with no real roots or real solutions. In the complex domain, the solutions are 1 +/- i where i is the imaginary square root of -1.
The two solutions are the conjugate complex numbers, +i*sqrt(11) and -i*sqrt(11), where i is the imaginary square root of -1.
many solutions
There are 120 solutions.
24
There are four solutions to 9x4 plus 27x3 - 4x2 - 12x equals 0. One of the solutions is x = -3.
Two solutions and they are:- x = 0 and y = 3
This quadratic equation has no solutions because the discriminant is less than zero.
zero solutions. If you plot these two lines, you will see that they are parallel and do not intersect.
1 solution
1
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7