(2x+5)(2x+1)
You need to rivse your question. It appears that there is not an equation here. 4*2+12x+9? You can't really solve this it is more of a statement. You can however simplify it to 12x+17- Whoever wrote this obviously can't read. It's supposed to be 4x^2+12x+9 (2x+3)(2x+3)
x2-5-4x2+3x = 0 -3x2+3x-5 = 0 or as 3x2-3x+5 = 0
1/2 , 3/2
4x2 + x2 = 8 + x2
4x2 = -12x, divide both sides by 4x: x = -3
(2x + 3)(2x + 3)
4x2 + 12x + 5 = (2x + 1)(2x + 5).
4x2 - 12x + 9 = 5; whence, 2x - 3 = ±√5, and 2x = 3 ±√5. Therefore, x = ½ (3 ±√5).
Only if the value of c is 9 because:- 4x2+12x+9 = (2x+3)(2x+3)
4x2+12x = 4x(x+3) when factored
12x * 4x2 = 48x3
4x2 + 12x + 5 = 4x2 + 2x + 10x + 5 = 2x(2x+1) + 5(2x+1) = (2x+1)(2x+5)
4x2 is 8+ 12x + 3 collect like terms, 8+3= 11, 12x+11 to solve for x, transpose the 11 to the other side of the = sign, 12x=-11, divide by 12, x=-11/12
(2x+5)(2x+1)
4(x + 2)(x + 1)
4x2 plus 3=11