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Na+ plus OH- plus H+ equals H2O plus Na+ plus Cl-
The binding of Na+ ions to the pump
2NaH2 + O2 yields 2Na + 2H2O
P + Na(OH) + H20 = NaH2PO2 + PH3
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Na+ and Cl- are spectator ions.
Na+ and Cl-
Na+, K+,Li+, NH4 + and NO3 - are always spectator ions because they are always soluble
Hydrochloric acid and sodium hydroxide yield salt and water H+ + Cl- + Na+ + OH- --> Na+ + Cl- + H2OComment:In solutions you better leave unchanged ions ( Cl- and Na+) out of the balanced equation: called to be 'tribune ions' (people on the tribune don't take part in the 'match'):H+ + OH- --> H2O This looks simpler than: H+ + Cl - + Na + + OH- --> Na + + Cl - + H2O
spectator ions are: Na and NO3
Na+1 and I-1; the Ba+2 and SO4-2 precipitate as BaSO4.
H^+(aq) + C2H3O2^-(aq) + Na^+(aq) + OH^-(aq) = Na^+(aq) + C2H3O2^-(aq) + H2O(L)Reducing (by crossing out repeated [spectator] ions) gives H^+(aq) + OH^-(aq) = H2O(L)
Traditionally, if this reaction is taking place in solution, instead of writing NaOH + HCl --> NaCl + H2O you would write OH- + H+ --> H2O because when the compounds are in the presence of water, they do not actually attach to each other. NaOH becomes Na+ and OH- ions, and Na+ will not attach to anything else in water. Similarly, HCl becomes H+ and Cl- ions, and Cl- will not attach to Na+ in water. (Think about salt in water; it dissolves). Na+ and Cl- are called "spectator ions" because they do not participate in the reaction. They are just floating around in the beaker, so scientists do not include them in the final equation. What is left is OH- and H+ ions which makes H2O.
K+ and NO3- because KOH + HNO3 (yields) H2O + KNO3
Na+H2o+H2=2 Nhoh
In water? If so - salt solution - the fllowing hydrated ions - H+, OH-, Na+, Cl- plus molecular H2O. Sugar solution - hydrated sugar molecules, molecular H2O and H+ and OH- hydrated ions
in most reactions it is, however if it is said that it is a liquid solid or gas it is not a spectator ion