Volume = length x width x depth = 4xy cm3 = 135 cm3 [1]
Surface area = 2 x (length x width + length x depth + width x depth)
= 2 x (xy + 4x + 4y) cm2 = 163.5 cm2 [2]
From [1]: 4xy = 135 → y = 135/4x
Substituting in [2]:
2(xy + 4x + 4y) = 163.5
→ 2(x(135/4x) + 4x + 4(135/4x)) = 163.5
→ 135/2 + 8x + 270/x = 327/2
→ -96 + 8x + 270/x = 0
→ 4x2 - 48x + 135 = 0
→ (2x - 15)(2x - 9) = 0
→ x = 7.5 or 4.5
→ y = 4.5 or 7.5 (respectively).
Thus the cuboid is 7.5 cm by 4.5 cm by 4 cm.
Assuming these are the dimensions of a cuboid, 13 square cm.
There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.
There is not enough information to calculate the dimensions.
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
The following are some shapes having a square cross section: a cube, a cuboid, a square pyramid.
Let its dimensions be a, b and c:- Surface area of the cuboid: 2*(a*b)+2*(b*c)+2*(a*c) in square units
Assuming these are the dimensions of a cuboid, 13 square cm.
Following are the formulas of cuboid. Let the dimensions of the cuboid be l (length), w(width) and h (height). Lateral surface area of the cuboid = perimeter of rectangular base x height = 2(l + w)h square units= 2h(l + w) square units; Total surface area (TSA) = 2 (lw + wh + hl); Volume of cuboid (V) = lwh. Length of diagonal of one side is √(l^2 + w^2), √(w^2 + h^2), √(h^2 + l^2) - depending upon side. Length of diagonal across the cuboid is √(l^2 + w^2 + h^2)
A square prism is always a cuboid.
There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.There are three measures given but the shape is not specified. I shall assume that it is a cuboid (rectangular prism).The total surface area of the shape is 2941.33... square feet.
There is not enough information to calculate the dimensions.
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.
For a cuboid, the total surface area = 2*(L*B + B*H + H*L) square units where L = length, B = breadth and H = height.In the case of a cube, L = B = H and so the total surface area is 6*L^2 square units.
The following are some shapes having a square cross section: a cube, a cuboid, a square pyramid.
A cuboid can have 2, 4 or 6 square faces.
It is the sum of each of the six square faces. Each face has an area of s2 square units where s is the side length. So the total surface area is 6s2 square units.
You imagine the cuboid, (which will have 6 faces) and work out the dimension of the edges for each individual face (there will be pairs of opposite faces with identical dimensions):3 * 4 = 123 * 4 = 123 * 2 = 63 * 2 = 62 * 4 = 82 * 4 = 812 + 12 + 6 + 6 + 8 + 8 = 52So the surface area is 52 square units.