You imagine the cuboid, (which will have 6 faces) and work out the dimension of the edges for each individual face (there will be pairs of opposite faces with identical dimensions):
12 + 12 + 6 + 6 + 8 + 8 = 52
So the surface area is 52 square units.
Lateral surface area of a cuboid = 2 (Length + Breadth) × Height Lateral surface area of a cube = 4 × Side2
For a cuboid, the total surface area = 2*(L*B + B*H + H*L) square units where L = length, B = breadth and H = height.In the case of a cube, L = B = H and so the total surface area is 6*L^2 square units.
The surface area is the total area of all the faces. For a cuboid, all these faces will be rectangular. Example: Find the surface area of a 2 x 4 x 5 cm cuboid. The area of the faces will be: 2 x 4 = 8 cm2 2 x 5 = 10 cm2 4 x 5 =20 cm2 Adding these up give an area of 38 cm2. However we now need to multiply our answer by 2 as there are exactly two of each face. So our final answer is 38 x 2 = 76 cm2.
If you assume that the shape is a cuboid, its area is 10 cm2 and its volume is 2 cm3
2(pi)radius^2
To calculate the surface area of a cuboid, use the formula (2(ab + ac + bc)), where (a), (b), and (c) are the dimensions. For a cuboid with dimensions 2, 4, and 6, the surface area is (2(2 \times 4 + 2 \times 6 + 4 \times 6)). This simplifies to (2(8 + 12 + 24) = 2 \times 44 = 88). Thus, the surface area of the cuboid is 88 square units.
Lateral surface area of a cuboid = 2 (Length + Breadth) × Height Lateral surface area of a cube = 4 × Side2
The surface area of a cuboid can be calculated using the formula (2(ab + ac + bc)), where (a), (b), and (c) are the dimensions of the cuboid. For a cuboid with dimensions 1, 2, and 3, the surface area is (2(1 \cdot 2 + 1 \cdot 3 + 2 \cdot 3) = 2(2 + 3 + 6) = 2 \times 11 = 22) square units. Therefore, the surface area of the 1x2x3 cuboid is 22 square units.
Let its dimensions be a, b and c:- Surface area of the cuboid: 2*(a*b)+2*(b*c)+2*(a*c) in square units
The surface area ( A ) of a cuboid can be calculated using the formula ( A = 2(lw + lh + wh) ), where ( l ), ( w ), and ( h ) are the length, width, and height, respectively. For a cuboid with dimensions 9 mm, 3 mm, and 2 mm, the surface area is ( A = 2(9 \times 3 + 9 \times 2 + 3 \times 2) = 2(27 + 18 + 6) = 2(51) = 102 , \text{mm}^2 ). Therefore, the surface area of the cuboid is 102 mm².
Surface area of a cuboid with sides x, y and z is 2(xy+yz+zx) So surface = 2*(1.45*1.45 + 1.45*5 + 5*1.45) = 2*16.6025 = 33.205
The answer should be: (2*a*b)+(2*b*c)+(2*c*a)
The surface area ( A ) of a cuboid can be calculated using the formula ( A = 2(lw + lh + wh) ), where ( l ), ( w ), and ( h ) are the length, width, and height, respectively. For a cuboid measuring 3 cm by 3 cm by 4 cm, the surface area is ( A = 2(3 \times 3 + 3 \times 4 + 3 \times 4) = 2(9 + 12 + 12) = 2(33) = 66 ) cm². Thus, the surface area of the cuboid is 66 cm².
To calculate a cuboid, you need to determine its volume or surface area. The volume is calculated using the formula ( V = l \times w \times h ), where ( l ) is the length, ( w ) is the width, and ( h ) is the height. The surface area can be calculated using the formula ( SA = 2(lw + lh + wh) ), summing the areas of all six rectangular faces. Simply plug in the measurements of the cuboid into these formulas to find the desired values.
Volume = Height × Width × Depth Surface area=2(lw+wh+hl)
The surface area of a cuboid is 2*(L*B + B*H + H*L) where L = length, B = breadth and H = height. In a cube, L = B = H and so surface area = 6*L2
The surface area ( A ) of a cuboid can be calculated using the formula ( A = 2(lw + lh + wh) ), where ( l ), ( w ), and ( h ) are the length, width, and height, respectively. For a cuboid with dimensions 4 cm, 5 cm, and 10 cm, the surface area is ( A = 2(4 \times 5 + 4 \times 10 + 5 \times 10) = 2(20 + 40 + 50) = 2(110) = 220 ) cm². Thus, the surface area of the cuboid is 220 cm².