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Volume: 1*x*y = 12 or as xy = 12

Area: (2*1*x)+(2*x*y)+(2*1*y) = 38 or as x+xy+y = 19

So: x+12+y = 19 => x+y = 7 and y = 7-x

So: x(7-x) = 12 => 7x-x2-12 = 0

Solving the quadratic equation: x = 3 or x = 4

Values by substitution: when x = 3cm then y = 4cm

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Q: What are the values of x and y of a cuboid with dimensions of 1 cm by x cm by y cm with a volume of 12 cubic cm and a surface area of 38 square cm showing work?
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