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Q: What are the x solutions for 10x 2-6436x 6x2?

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6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.

It has two solutions and they are: x = 3.230396696 and x = -2.063730029

6x2 + 10x = 5 6x2 + 10x - 5 = 0 The roots are 1/(2*6)* [-10 +/- sqrt(102 - 4*6*(-5))] = 1/(2*6) * [-10 +/- sqrt 220] =1/6 * [-5 +/- sqrt 55] So x = -2.0694 or 0.403

If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5

Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0

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6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.

It has two solutions and they are: x = 3.230396696 and x = -2.063730029

10x2 - 56 = 88 - 6x2 : 10x2 + 6x2 = 88 + 56 : 16x2 = 144 : x2 = 9 : x = ± 3

If that was - 10x + 21, it would factor to (x - 3)(x - 7) If that was + 10x + 21, it would factor to (x + 3)(x + 7) As it is, the solutions are irrational.

10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.

6x2 + 10x = 5 6x2 + 10x - 5 = 0 The roots are 1/(2*6)* [-10 +/- sqrt(102 - 4*6*(-5))] = 1/(2*6) * [-10 +/- sqrt 220] =1/6 * [-5 +/- sqrt 55] So x = -2.0694 or 0.403

If: 10x2-64 = 36+6x2 Then: 4x2-100 = 0 And: (2x-10)(2x+10) = 0 So: x = 5 or x = -5

15x2-56 = 88+6x2 15x2-6x2-56-88 = 0 9x2-144 = 0 Divide all terms by 9:- x2-16 = 0 (x-4)(x+4) = 0 x = 4 or x = -4

An equation would be....,X2 - 10X + 16 = 0easy factoring(X - 2)(X - 8)==========So.X = 2====

Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5

-3 times the square root of 158 3 times the square root of 158

If you mean: x-3x+27 = 8x-3 then -10x = -30 and x =3