Equation: 10x^2 -29x +10 = 0
When factored: (2x-5)(5x-2) = 0
Its solutions: x = 5/2 or x = 2/5
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
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Pythagoras.
The Pythagoream Thereom is a^2 + b^2 = c^2. Written out it is a squared plus b squared equals c squared.
a squared plus b squared equals c squared usually expressed as: a2+b2 = c2
It can not be factored because its discriminant is less than zero
x = -½
If you mean: x2+9x+20 then it is (x+4)(x+5) = 0 when factored
y = 3x + 21x2 = 3x(1 + 7x)
The expression d squared plus 16d plus 48 can be factored as (d + 4)(d + 12).
The solutions are: x = 4, y = 2 and x = -4, y = -2
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
It is (x-1)(x-8) when factored
b2 + 8x + 7. 7 and 1 add up to be 8 and multiply to be 7. So therefore, it would be factored as: (b+1)(b+7)
9x squared plus 16 = 0 factored is plus and minus 4/3 i.
2x2+5x+3 = (2x+3)(x+1) when factored
(a - 2b)(2a - b)