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The question contains an algebraic expression but, since there is no equality sign, there is no equation to solve.
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Is it possible for an equation to have many solutions and can an equation have no solutions?
Yes and yes. eg x = y + 1 has an infinite number of solutions, and {sin(x) + cos(x) = 2} does not have a solution.
Which statement about the quadratic equation below is true -4.5x2 plus 72 0 A) The equation has x 4 as its only solution B) The equation has no real solutions C) The equation has x 4 and x?
I gotchu homie: It's The equation has x = 4 and x = -4 as its only solutions.
What are the solutions to the equation 3(x-4)(x 5)0?
Without an equality sign the given expression can't be considered to be an equation and so therefore there are no solutions.
How do you write a quadratic equation using only solutions 9 and 1?
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
How you find the solution of a quadratic equation by graphing its quadratic equation?
When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.
When you square each side of an equation is the resulting equation equivalent to the original?
No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2
How many solutions for x does the following equation have?
It has the following solutions.
Is it possible for an equation to have many solutions and can an equation have no solutions?
Yes and yes. eg x = y + 1 has an infinite number of solutions, and {sin(x) + cos(x) = 2} does not have a solution.
Which statement about the quadratic equation below is true -4.5x2 plus 72 0 A) The equation has x 4 as its only solution B) The equation has no real solutions C) The equation has x 4 and x?
I gotchu homie: It's The equation has x = 4 and x = -4 as its only solutions.
What does one solution mean in math?
An equation may have zero, one, or more solutions (this is also true for a system of equations). The equation 2 + x = 5 has only solution, for example. x can only equal 3, so there is one solution. (An example of an equation with more that one solution is x2 = 4. In this case x can equal 2 or -2, so this equation has two solutions. An example of an equation with an infinite number of solutions is x + 6 = 3*2 + x. x can equal any number to make this equation true, so it has an infinite number of solutions. The equation x = x + 1 is an example of an equation with no solutions.)
What are the solutions for X squared minus 5x equals 6?
The solutions to the quadratic equation are: x = -1 and x = 6
What are the solutions to the equation 3(x-4)(x 5)0?
Without an equality sign the given expression can't be considered to be an equation and so therefore there are no solutions.
How do you write a quadratic equation using only solutions 9 and 1?
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
How many solutions does an equation have?
Equations can have many solutions. The equation of a straight line, for example, defines all points on the line. Even a simple equation such as x+y=5 can have a variety of solutions (x=1 when y=4, x=2 when y=3 and so on)
How you find the solution of a quadratic equation by graphing its quadratic equation?
When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.
How many solutions are there in the quadratic equation x2 - 4x - 77 equals 0?
There are two solutions for x: x=11 and x=-7
Write a quadratic equation with these numbers -7 and -4 as solutions?
-3
