Write the quadratic equation in the form ax2 + bx + c = 0 then the roots (solutions) of the equation are: [-b ± √(b2 - 4*a*c)]/(2*a)
0x2 + 1x - 7 = 0
readuse the answer
The easiest way to write a generic algorithm is to simply use the quadratic formula. If it is a computer program, ask the user for the coefficients a, b, and c of the generic equation ax2 + bx + c = 0, then just replace them in the quadratic formula.
It isn't entirely clear what you mean "for 15 and 10". If you want an equation that has those solutions, you can simply write:(x - 15) (x - 10) = 0 If you wish, you can multiply the polynomials out. The solutions will be the same, but the resulting equation will be harder to solve.
Write the quadratic equation in the form ax2 + bx + c = 0 then the roots (solutions) of the equation are: [-b ± √(b2 - 4*a*c)]/(2*a)
(x + 5) (x + 1) = 0x2 + 6x + 5 = 0
12
Write an algorithm to find the root of quadratic equation
Just write the equation as: (x - 11)(x - 3) = 0 and convert it to any form you like.
0x2 + 1x - 7 = 0
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
Ax2 + Bx + C = 0'A', 'B', and 'C' are numbers (constants).
Write the quadratic equation in the standard form: ax2 + bx + c = 0 Then calculate the discriminant = b2 - 4ac If the discriminant is greater than zero, there are two distinct real solutions. If the discriminant is zero, there is one real solution. If the discriminany is less than zero, there are no real solutions (there will be two distinct imaginary solutions).
x2 - 4x + 4 or (x - 2)2
readuse the answer
2000X=Y2KoverZzz?