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Is it possible for an equation to have many solutions and can an equation have no solutions?
Yes and yes. eg x = y + 1 has an infinite number of solutions, and {sin(x) + cos(x) = 2} does not have a solution.
Which statement about the quadratic equation below is true -4.5x2 plus 72 0 A) The equation has x 4 as its only solution B) The equation has no real solutions C) The equation has x 4 and x?
I gotchu homie: It's The equation has x = 4 and x = -4 as its only solutions.
What are the solutions to the equation 3(x-4)(x 5)0?
Without an equality sign the given expression can't be considered to be an equation and so therefore there are no solutions.
How do you write a quadratic equation using only solutions 9 and 1?
Solutions: x = 9 and x = 1 Factored: (x-9(x-1) = 0 Equation: x2-10x+9 = 0
How you find the solution of a quadratic equation by graphing its quadratic equation?
When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.
