Solutions: x = 9 and x = 1
Factored: (x-9(x-1) = 0
Equation: x2-10x+9 = 0
Just write the equation as: (x - 11)(x - 3) = 0 and convert it to any form you like.
To express the equation (2x^2 + 3x + 90) in standard quadratic form, we can simply write it as (2x^2 + 3x + 90 = 0). This represents a quadratic equation where (a = 2), (b = 3), and (c = 90). The equation can be solved for (x) using the quadratic formula or factoring, if applicable.
(x + 5) (x + 1) = 0x2 + 6x + 5 = 0
ax2 + bx + c
computer scince
12
To solve a quadratic equation using factoring, follow these steps: Write the equation in the form ax2 bx c 0. Factor the quadratic expression on the left side of the equation. Set each factor equal to zero and solve for x. Check the solutions by substituting them back into the original equation. The solutions are the values of x that make the equation true.
Write the quadratic equation in the form ax2 + bx + c = 0 then the roots (solutions) of the equation are: [-b ± √(b2 - 4*a*c)]/(2*a)
Write an algorithm to find the root of quadratic equation
Just write the equation as: (x - 11)(x - 3) = 0 and convert it to any form you like.
-3
Write the quadratic equation in the standard form: ax2 + bx + c = 0 Then calculate the discriminant = b2 - 4ac If the discriminant is greater than zero, there are two distinct real solutions. If the discriminant is zero, there is one real solution. If the discriminany is less than zero, there are no real solutions (there will be two distinct imaginary solutions).
2000X=Y2KoverZzz?
readuse the answer
(x + 5) (x + 1) = 0x2 + 6x + 5 = 0
An example of a quadratic equation is ( ax2 bx c 0 ), where ( a ), ( b ), and ( c ) are constants and ( x ) is the variable.
computer scince