Just write the equation as: (x - 11)(x - 3) = 0 and convert it to any form you like.
(x + 5) (x + 1) = 0x2 + 6x + 5 = 0
computer scince
ax2 + bx + c
Write the quadratic equation in the form ax2 + bx + c = 0 The roots are equal if and only if b2 - 4ac = 0. The expression, b2-4ac is called the [quadratic] discriminant.
12
Write the quadratic equation in the form ax2 + bx + c = 0 then the roots (solutions) of the equation are: [-b ± √(b2 - 4*a*c)]/(2*a)
Write an algorithm to find the root of quadratic equation
Just write the equation as: (x - 11)(x - 3) = 0 and convert it to any form you like.
-3
Write the quadratic equation in the standard form: ax2 + bx + c = 0 Then calculate the discriminant = b2 - 4ac If the discriminant is greater than zero, there are two distinct real solutions. If the discriminant is zero, there is one real solution. If the discriminany is less than zero, there are no real solutions (there will be two distinct imaginary solutions).
(x + 5) (x + 1) = 0x2 + 6x + 5 = 0
readuse the answer
2000X=Y2KoverZzz?
computer scince
ax2 + bx + c
Simply write that "no solutions are available for <equation>".