x+x+1+x+2=216
3x+3=216
3x=213
71,72,73
108, 162, 216 & 270
215 + 216 + 217 + 218 = 866
No.
83, 84 and 85 if you add them.
There is no such set of numbers.
3, 5 and 7 are consecutive odd prime numbers.
Do you mean:"What three consecutive numbers add up to 99?" If you do, then the numbers are 32, 33, 34.
3332, 3333 and 3334 add up to 9999 - there are no three consecutive numbers that add up to 10,000.
Let the 3 consecutive numbers be (a-1), a, and (a+1) So, (a-1) + (a) + (a+1) = 216 You add the left-hand side and get: 3a =216 You divide and get: a = 216/3 = 72 So, (a-1) = 72-1 = 71 a = 72 (a+1)= 72+1 = 73 Check: 71+72+73 = 216
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
divide 216 by 3 (72) subtract 1 and add 1 71, 72 and 73
EVERY three consecutive numbers add to a multiple of 3: Proof: numbers are n, n + 1 and n + 2. The total is 3n + 3 or 3(n + 1) This means that for any three consecutive numbers, the total is 3 times the middle number.