Best Answer

256, 257, 258

Let the three numbers be n-1, n, n+1, then:

(n-1) + n + (n+1) = 771

→ 3n = 771

→ n = 257

→ the three numbers are 257-1 = 256, 257 and 257+1 = 258

More answers

126, 127, 128

Q: What are three consecutive numbers that sum to 771?

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