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256, 257, 258

Let the three numbers be n-1, n, n+1, then:

(n-1) + n + (n+1) = 771

→ 3n = 771

→ n = 257

→ the three numbers are 257-1 = 256, 257 and 257+1 = 258

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11y ago

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16y ago

126, 127, 128

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Q: What are three consecutive numbers that sum to 771?
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