Q: What are two consecutive numbers with the product of 9120?

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Find two consecutive numbers with the value of 4160

There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)

The numbers are 14 and 15.

The numbers are 103 and 104.

The numbers are 64 and 65.

Related questions

Two consecutive numbers can be represented as n and (n + 1), then :- n(n + 1) = 9120 n² + n - 9120 = 0 . . . this can be factored as, (n + 96)(n - 95) = 0 . . . so the two numbers are 95 and 96 (or -96 and -95).

Find two consecutive numbers with the value of 4160

Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.

There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)

two consecutive numbers with the product of 1722 = 41 & 42

The product of two consecutive even integers is 840.find these numbers

23x24.

Yes.

The numbers are 28 and 29.

The numbers are 56 and 57.

The numbers are 24 and 25.

The numbers are 43 and 44.