If you mean consecutive numbers then they are 23*24 = 552
Find two consecutive numbers with the value of 4160
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
Let n be the lower number then the higher number is n + 1. n (n + 1 ) = 552 : n² + n - 552 = 0 Solving for the roots of a quadratic equation gives :- n = [-1 ± √(1 + 2208)] ÷ 2 = [-1 ± √2209] ÷ 2 = [-1 ± 47]÷ 2 Taking just the positive root gives n = -½ + 23½ = 23 The two consecutive numbers are therefore 23 and 24. Whilst this is a very accurate but complicated process a much quicker result can be achieved by taking the square root of 552 = 23.5 (approx). Two consecutive numbers producing 552 must lie either side of the square root. A simple multiplication will reveal that the numbers are 23 and 24.
The numbers are 14 and 15.
23x24.
If you mean consecutive numbers then they are 23*24 = 552
To find two consecutive numbers with a product of 552, we can set up an equation using algebra. Let's call the first number x, and the next consecutive number x+1. The equation we can set up is x(x+1) = 552. By solving this quadratic equation, we find that the two consecutive numbers are 23 and 24, as 23*24 = 552.
Find two consecutive numbers with the value of 4160
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
Two consecutive two digit numbers that when multiplied give the product of 812 are 28 and 29.
two consecutive numbers with the product of 1722 = 41 & 42
Let n be the lower number then the higher number is n + 1. n (n + 1 ) = 552 : n² + n - 552 = 0 Solving for the roots of a quadratic equation gives :- n = [-1 ± √(1 + 2208)] ÷ 2 = [-1 ± √2209] ÷ 2 = [-1 ± 47]÷ 2 Taking just the positive root gives n = -½ + 23½ = 23 The two consecutive numbers are therefore 23 and 24. Whilst this is a very accurate but complicated process a much quicker result can be achieved by taking the square root of 552 = 23.5 (approx). Two consecutive numbers producing 552 must lie either side of the square root. A simple multiplication will reveal that the numbers are 23 and 24.
The numbers are 28 and 29.
The numbers are 56 and 57.
The numbers are 24 and 25.
The numbers are 43 and 44.