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Q: What are two factors of 48 with a sum of 26?

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24 and 2 2 X 24=48 2+24=26

24 and 16 are factors of 48

16 and 3

4 & 12.

48

The common factors of 26 and 48 are: 1 and 2

24 & 2 Factors of 48, that is, the 2 numbers that when multiplied together equal 48 are: a) 1 & 48; sum is 49 - nope b) 2 & 24; sum is 26 - ding! ding! ding! ding! c) 3 & 16; sum is 19 - nope d) 4 & 12; sum is 16 - nope e) 6 & 8; sum is 14 - nope

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48. Their sum is 124.

48

124

22 and 26

The common factors of 42 and 48 are: 1, 2, 3, 6 which gives their sum as 12.

The odd factors of 70 are: 1, 5, 7, and 35. The sum of these factors is 48.

c+b=ac and b - addendsa - sumexamples:26+67=93(26) and (93) are the addends and the number (93) is the sum of the two addends12+48=60(12) and (48) are the addends.(60) is the sum of (12 and 48) the two addends.This answer was improved by 3na snogoy. Please do not change this answer. =)

48

2

1 + 3 = 4

1,2,13,26 1,2,3,4,6,8,12,16,24,48 1,2,31,62

the sum of two whole numbers are 77 .their difference is 48.what are the two numbers

1 + 35 + 5 + 7 = 48

They are: 29+19 = 48

The factors of 26 are 1, 2, 13, 26 The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, 48 The factors of 62 are 1, 2, 31, 62

The odd positive integer factors of 70 are: 1 5 7 35 The sum of these factors is 1 + 5 + 7 + 35 = 48

If the two numbers have a hcf of 48 then both numbers must be multiples of 48. 384 ÷ 48 = 8 .........Taking the paired factors of 48 of both numbers then the sum of the other factors = 8 but there can be no other common factor. 1 + 7 = 8, 3 + 5 = 8 are solutions but 2 + 6 = 8 and 4 + 4 = 8 are not, as further common factors of 2 and 4 respectively are present which would increase the hcf to 96 and 192. The numbers are 1 x 48 and 7 x 48 → 48 and 336 and.....................3 x 48 and 5 x 48 → 144 and 240

46