=The Two numbers are 41 and 13.=
10 and 3
This is easily solved by using two equations in 2 unknowns and solving the system. x + y = 111 x - y = 43 If have not yet had the pleasure of studying algebra and the answer is important to you, you could hope the numbers are positive integers and try all pair of numbers whose sum is 43: 1,42 2,41 3,40 and so on, until you find a pair whose difference is 43.
The numbers are -16 and -15.
The two numbers are 5 and -6. 5x(-6) = -30 so the product is -30 and 5+(-6) = -1 so the sum is -1
29 and 36
6 & 4
37 and 21
19 and 34
20 & 3
28 and 36
12 and 24?
18 and -6.
38-4=34
The answer is 39 and 19 (: hope this helps!
That's not possible... * * * * * How about -5 and 25?
Find the 2 numbers whose difference is two and whose sum is 480.