=The Two numbers are 41 and 13.=
10 and 3
This is easily solved by using two equations in 2 unknowns and solving the system. x + y = 111 x - y = 43 If have not yet had the pleasure of studying algebra and the answer is important to you, you could hope the numbers are positive integers and try all pair of numbers whose sum is 43: 1,42 2,41 3,40 and so on, until you find a pair whose difference is 43.
The numbers are -16 and -15.
The numbers are -134, -132 and -130.
29 and 36
6 & 4
37 and 21
19 and 34
20 & 3
28 and 36
12 and 24?
18 and -6.
38-4=34
Let's call the two numbers x and y. We can set up a system of equations based on the given information: x + y = 51 and x - y = 13. By solving this system simultaneously, we can find the values of x and y. Adding the two equations together, we get 2x = 64, so x = 32. Substituting x back into the first equation, we find that y = 19. Therefore, the two numbers are 32 and 19.
That's not possible... * * * * * How about -5 and 25?
Find the 2 numbers whose difference is two and whose sum is 480.