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Q: What area are volume and rate classified under?
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Volume and aate are classified under which area of consideration?

when delivering a briefing volume and rate are classified under which area of consideration


When delivering a briefing 'volume and rate' are classified under which area of consideration?

verbal


When delivering a brriefing volume and rate are classified under which area of consideration?

verval consideration


When delivering a briefing'volume and rate' are classified under which area of consideration?

verbal consideration


When delivering a briefing volume and rate it considered under which area of consideration?

verbal consideration


How does surface area to volume ratio of a cell affect rate of diffusion?

The surface area to volume ratio of a cell affects the rate of diffusion in that the higher the ratio, the faster the rate of diffusion. This is a directly proportional relationship.


As a cell becomes larger what happens to its surface area and volume?

The Volume increases faster than the Surface Area


A derivative is to the rate of change as an integral is to?

A derivative is to the rate of change asan integral is to area/volume.


What is volume and rate considered when delivering a brief?

The area of consideration when delivering a brief of volume and rate is a verbal consideration. This is such because delivering a brief is oral.


What the relationships between the surface area of an object and the volume as the object increases in size?

They both increase. The rate of increase of the surface area is equivalent to the rate of increase of the volume raised to the power 2/3.


How does surface area affect decomposition rate?

The rate of combustion directly proportional to the surface area of combining naterials


How to show that the rate of change of the volume of a cube with respect to the length of its edges is equal to have the surface area of the cube?

If the length of an edge is x, the volume is x3 To find the rate of change of the volume with respect to x, differentiate: d(x3)/dx = 3x2 The area of one face is x2 There are six faces so the total surface area is 6x2 Therefore the rate of change of volume, 3x2 , is half of 6x2 , the surface area.