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Btech is Bachelor of Technology

BE is Bachelor of Engineering

Q: What d difference bw BTECH n BE?

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For any index n (>1) calculate D(n) = U(n) - U(n-1). If this is the same for all integers n (>1) then D is the common difference. The sign of D determines whether the common difference is positive or negative.

In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant. That is, Arithmetic progression U(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1) + d = U(1) + (n-1)*d Geometric progression U(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1)*r = U(1)*r^(n-1).

In a sequence of numbers, a(1), a(2), a(3), ... , a(n), a(n+1), ... he first differences are a(2) - a(1), a(3) - a(2), ... , a(n+1) - a(n) , ... Alternatively, d the sequence of first differences is given by d(n) = a(n+1) - a(n), n = 1, 2, 3, ...

An arithmetic sequence is a sequence of numbers such that the difference between successive terms is a constant. This constant is called the common difference and is usually denoted by d. If the first term is a, then the iterative definition of the sequence is U(1) = a, and U(n+1) = U(n) + d for n = 1, 2, 3, ... Equivalently, the position-to-term rule which defines the sequence is U(n) = a + (n-1)*d for n = 1, 2, 3, ...

a + (n-1)d = last number where a is the first number d is the common difference.

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For any index n (>1) calculate D(n) = U(n) - U(n-1). If this is the same for all integers n (>1) then D is the common difference. The sign of D determines whether the common difference is positive or negative.

Piezoelectricity is the generation of an electric charge in response to mechanical stress or pressure, while pyroelectricity is the generation of an electric charge in response to changes in temperature. Both phenomena involve the production of electrical charge in certain materials but are triggered by different stimuli.

In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant. That is, Arithmetic progression U(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1) + d = U(1) + (n-1)*d Geometric progression U(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ... Equivalently, U(n) = U(n-1)*r = U(1)*r^(n-1).

It will simply decrease (if there is no atmosphere)

In a sequence of numbers, a(1), a(2), a(3), ... , a(n), a(n+1), ... he first differences are a(2) - a(1), a(3) - a(2), ... , a(n+1) - a(n) , ... Alternatively, d the sequence of first differences is given by d(n) = a(n+1) - a(n), n = 1, 2, 3, ...

In an arithmetic progression the difference between each term (except the first) and the one before is a constant. In a geometric progression, their ratio is a constant.That is,Arithmetic progressionU(n) - U(n-1) = d, where d, the common difference, is a constant and n = 2, 3, 4, ...Equivalently,U(n) = U(n-1) + d = U(1) + (n-1)*dGeometric progressionU(n) / U(n-1) = r, where r, the common ratio is a non-zero constant and n = 2, 3, 4, ...Equivalently,U(n) = U(n-1)*r = U(1)*r^(n-1).

An arithmetic sequence is a sequence of numbers such that the difference between successive terms is a constant. This constant is called the common difference and is usually denoted by d. If the first term is a, then the iterative definition of the sequence is U(1) = a, and U(n+1) = U(n) + d for n = 1, 2, 3, ... Equivalently, the position-to-term rule which defines the sequence is U(n) = a + (n-1)*d for n = 1, 2, 3, ...

a + (n-1)d = last number where a is the first number d is the common difference.

clearly the given series is an arithmetic progression with a common difference of -11,that is every term is obtained by subtracting 11 from the previous term for any A.P, n-th term is a(n)=a(1)+ (n-1)d where a(1)=first term and d=common difference here a(1)=100, and d= -11 so, a(n)=100+(n-1)x(-11) or, a(n)=111-11n

Catagory rank is your rank in your category(ie - General, SC, ST, OBC). Overall ranking is your rank in all category, including, general, ST, SC, OBC.

Sum = n/2[2Xa1+(n-1)d] where n is last number, a1 is the first number & d is the common difference between the numbers, here d=2 for the even /odd numbers. Sum = n/2 [2Xa1+(n-1)2]

The general (or nth) term is given by the equation t(n) = a + (n-1)d where a is the first term and d is the common difference between successive terms.