tn = a + (n - 1)d
where a is the first term and d is the difference between each term.
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The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
It appears that a number of -79 is missing in the sequence and so if you meant -58 -65 -72 -79 -86 then the nth term is -7n-51 which makes 6th term in the sequence -93
The nth term is referring to any term in the arithmetic sequence. You would figure out the formula an = a1+(n-1)d-10where an is your y-value, a1 is your first term in a number sequence (your x-value), n is the term you're trying to find, and d is the amount you're increasing by.
The given sequence is an arithmetic sequence with a common difference of 7. To find the nth term of an arithmetic sequence, you can use the formula: nth term = first term + (n-1) * common difference. In this case, the first term is 12 and the common difference is 7. Therefore, the nth term of this sequence would be 12 + (n-1) * 7.
It is a + 8d where a is the first term and d is the common difference.