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Q: What do you know about the divisor when the quotient of two numbers is the same as the dividend?

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the number is 0

0.0244

The three parts to a division problem are: Dividend, Divisor, and Qoutient. To calculate the value of any of the terms, two of the terms need to be known values. To calculate the dividend, multiply the quotient by the divisor.

If there is no remainder, you can use the relation:dividend = divisor x quotient If you ONLY know the divisor, you don't have enough information; though you can make up any number for the quotient, and multiply them together to get the dividend.

i dont know so you divied the

A sentence can say "The divisor in this division problem is 26". The word 'divisor' is a mathematics vocabulary that people get confused with 'dividend'. I hope you don't get mixed up with those similar words. By the way, 'dividend' means the number you are going to divide the divisor to get a quotient. A quotient is an answer to a division problem.That's all the vocabulary you need to know for a division problem.

Dividend divided by divisor equals quotient

Ask againA quotient is the result of division. We need another number. And we need to know which is the dividend and which is the divisor.

There are only two numbers in that case. For example 5 x 5 = 25 and 25/5 = 5. The fact family has only two sentences. Now from the equation it indicates that the product of the same numbers gives the dividend or dividend divided by divisor is the same number as the divisor since there are only two numbers in the fact family.

The dividend is the numerator and the divisor is the denominator. Basically, you divide the top number (numerator) by the bottom number (denominator).

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The easiest way to find the greatest common denominator of two integers with a computer program is to use the Euclidean algorithm. Of the most popular methods of finding the GCD of two numbers, the Euclidean algorithm does it with the least amount of work and requires the least amount of code.In order to understand the Euclidean algorithm, you'll need to know a few division terms:The dividend is the number to be divided.The divisor is the number being divided by.The quotient is the number of times the divisor divides into the dividend.The remainder is the amount "left over" when the divisor cannot go into the dividend an integral number of times.18A divided by 12B gives a quotient of 1C and a remainder of 6D. A is the dividend, B is the divisor, C is the quotient, and D is the remainder.The Euclidean algorithm works like this:Check if either of the two integers is 0. If so, there is no solution (Ø), as a number cannot share a GCD with zero. Besides, division by zero is a big no-no.Check if either of the two integers is 1. If so, 1 is the GCD.Divide the larger of the two integers by the smaller.Divide the divisor of the previous division operation by the remainder of the previous operation.Repeat step four until the remainder equals zero. When the remainder equals zero, the divisor of the last operation is the GCD.If you still don't get it, try looking at the Euclidean algorithm in action:Find the GCD of 84 and 18.Check to see if either 84 or 18 is equal to 0. Nope. Continue on...Check to see if either 84 or 18 is equal to 1. Nope. Continue on...Since 84 is larger than 18, divide 84 by 18. Quotient is 4, remainder is 12.Take the divisor of the last operation (18) and divide it by the remainder of the last operation (12). Quotient is 1, remainder is 6.Take the divisor of the last operation (12) and divide it by the remainder of the last operation (6). Quotient is 2, remainder is 0.When the remainder is 0, the divisor of the last operation is the GCD. So the GCD in this case is 6.You should now have a good grasp of how the Euclidean algorithm works. Now we need to turn it into code. We'll need three variables, all of them integers:int divisor, dividend, remainder;The purpose of the variables is self-explanatory. Next, we need to make a few decisions. We need to decide if the dividend or the divisor is 0. If that test is passed, then we need to decide if the dividend or the divisor is 1. If that test is passed, then we need make sure that dividend is larger than divisor.if(dividend 1) {printf("The GCD is 1.\n");}// Make sure the dividend is greater than the divisor.if(divisor > dividend) {remainder = dividend;dividend = divisor;divisor = remainder;}// Calculate the GCD.while(remainder != 0) {remainder = dividend % divisor;dividend = divisor;divisor = remainder;}// Display the answer to the user.printf("The GCD is %i.\n", dividend);}And the GCD lived happily ever after. The end.

The quotient is what you get when you divide two numbers. If both numbers are positive, the quotient will be positive. If both numbers are negative, the quotient will be positive. If one number is positive and one number is negative, their quotient will be negative.

Well, let's see. So we can try 285/9 It is 31 with 6 as it's remainder. You know that the dividend is the largest number, and the divisor would be less than the dividend. Since the divisor can't be any smaller than the remainder so would the dividend. Because it will be the only LARGEST number in the division equation.

Just go ahead and do it the usual way, using what you know about any long division that involves decimals. The answer will be less than ' 1 ', because the divisor doesn't go into the dividend even 1 time, but that shouldn't scare you.

The answer depends on what the divisor is. Without that information it is not possible to give a more useful answer.

Compatible Numbers numbers that are easy to compute mentally are called

You can't tell anything about the quotient until you know whatthe divisor is going to be.-- If I divide your 4,796 by 4, the quotient is 1,199 . . . 4 digits.-- And if I divide it by 2,398, the quotient is 2 . . . . only 1 digit.

When you are calculating the quotient of two numbers you are doing division.

You multiply the How_do_you_check_the_quotient_from_a_division_problemmy the divisor. If it equals the quoitent you are right. If your problem has a remainder then after multipling the dividend by the divisor, you add the remainder. For example... if you had 100/2(100 divided by 2), you would work it out. You should have 50 as your quoitent. You would do 50x2=100. 100 is the dividend! 103/2 has a remainder. Anyways, your quoitent should be 51R1(fifty-one remainder one). You check it by doing 51x2=102, then 102+1(your reainder). So it is 103.Extra helpful facts:If you have trouble remembering the steps for the traditional way to do division, all you have to do is remember this family: Dad says Dividedivisor), Mom says multiply(Divisor times quoitent so far), sister says subtract (dividend by the number under it), brother says bring down the next number(if there is one), Rover the dog gives the remainder(if there is one). If you don't know how to divide on paper this will NOT work!Read more: How_do_you_check_the_quotient_from_a_division_problem

To look at the numbers in the division problem

By following these steps, you do the prime factorisation using the ladder method; the steps show how the decision of the next divisor is made:At the top of the ladder start by setting the divisor to the smallest prime number (2).If the divisor does not divide into the dividend, set it to the next higher prime number and go back to step 2.Write the divisor in and divide by it to get the quotientIf the quotient is not 1 (and not a prime number) then using this quotient as the next dividend go to step 2.The list of divisors written in is the prime factorisation of the number.A reminder:Divisor - the number by which you are dividingDividend - the number into which you are dividingQuotient - the result of the division.The first few prime numbers are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29If you are not sure of the prime numbers, then start with 2, and when that fails, then use the odd numbers starting with 3 (that is the numbers 3, 5, 7, 9, 11, 13, 15, 17, ... in order) - not all of them are prime, but only the prime ones will divide in at any stage of the ladder as long as you use them in increasing size (or you make a mistake).example: Prime factorisation of 1638 using the steps:1. set divisor to 22. 1638 divisible by 23. 1638 ÷ 2 = 8194. dividend becomes 8192. 819 not divisible by 2, divisor becomes 32. 819 divisible by 33. 819 ÷ 3 = 2734. dividend becomes 2732. 273 divisible by 33. 273 ÷ 3 = 914. dividend becomes 912. 91 not divisible by 3, divisor becomes 52. 91 not divisible by 5, divisor becomes 72. 91 divisible by 73. 91 ÷ 7 = 134. dividend becomes 1313 is prime and so the need to go back to step 2 is unnecessary, but if the prime numbers are not known too well (see above), then the ladder could continue:2. 13 not divisible by 7, divisor becomes 92. 13 not divisible by 9, divisor becomes 11But if 9 is known not to be prime, then the above two steps would become a single step:2. 13 not divisible by 7, divisor becomes 11and the ladder would continue:2. 13 not divisible by 11, divisor becomes 132. 13 divisible by 133. 13 ÷ 13 = 14. quotient is 1leading the result:5. Prime factorisation is: 2 x 3 x 3 x 7 x 13When the dividend became 13, knowing the [smaller] prime numbers would help as it would be realised that 13 is prime and so there was no need to check 7 and 11.Drawn in ladder format, it looks like:2 | 1638...-------..3 | 819.....------..3 | 273.....------....7 | 91.......-----.........13Prime factorisation: 2 x 3 x 3 x 7 x 13

The dividend is the number you are dividing so you know it is 2 divided by something. Now to get a remainder of 2, you need the divisor to be larger than than 2, so: 2/3 works as does 2/4, 2/5,2/6,2/7 and so on

The 2nd factor is a square of the first one.

In equivalent division, you multiply (or divide) the dividend and the divisor by the same number to form a new problem that is easier to calculate metally. The new problem will produce the same quotient. ie: 2 divided by 1/2, if you multiply 2 by 2 you get 4 and if you multiply 1/2 by 2 you get 1. 4 divided by 1 = 4. This is the same as the answer to 2 divided by 1/2 (4), it is just easier to do in your head.