The exterior angles of any polygon add up to 360 degrees, regards of the number of sides. I'm thinking integers >2 -- if there is a way to make a polygon with negative, fractional, irrational, imaginary sides, then maybe that doesn't add up to 360. I'm also assuming Euclidian geometry -- on a sphere, for example, it wouldn't be 360.
If its a regular 9 sided polygon then the exterior angles are 40 degrees.
Providing that it is a regular 12 sided polygon then each exterior angle measures 30 degrees
If each exterior angle is 9 degrees then it is a regular 40 sided polygon.
Sum of exterior angles of any sided polygon is 360 so sum of exterior angle of 6 sided polygon (hexagon) is 360
360/number of sides = exterior angle
If it's a regular polygon then each exterior angle measures 36 degrees
Providing that it's a regular polygon then each exterior angle will measure 12 degrees.
The measure of the exterior angle of a 11-sided polygon = 360⁰/11 = 32 72/99⁰ = 32 8/11⁰
A regular 6-sided polygon has exterior angles of 60o(360o/6)If it is not regular, and one interiorangleis 140o, then the exterior angle at that vertex is 40o (180-40).
Each exterior angle measures 15 degrees
Each exterior angle is 72 degrees
Each exterior angle measures 36 degrees
The measure of 1 exterior angle of a regular 8-sided polygon is equivalent to 45 degrees. Hope I helped! :)
The sum of the exterior angles of any polygon, including a 27 sided one, is 360 degrees.
each angle= 20 degree
The sum of the exterior angle of any polygon is 360. So divide that by 8 in this case and each exterior angle has measure 360/8 or 45 degrees.
Each exterior angle measures 24 degrees
Each exterior angle measures 30 degrees
The exterior angle of a 52-sided polygon is 360/52 = 6.92 degrees, approx.
The sum of the exterior angles of any polygon is 360 degrees. If the polygon is regular then each exterior angle is 360 divided by the number of sides, so in this case each angle will be 10 degrees.