area of parallelogram= base*height perimeter= 2(length+breadth)
The area and perimeter of a parallelogram are not sufficient to determine its dimensions.
area is length times width
I smell a textbook question...
Perimeter of a Parallelogram = 2(a+b) where a and b are adjacent sides of a parallelogram
No. In fact a parallelogram does not add up. It has a perimeter, it has an area, it has four angles and they are or can be added up. The the parallelogram itself cannot.
I don't know about the relation in the perimeters of a triangle and a parallelogram but if a triangle is on the same base on which the parallelogram is and the triangle is between the same parallel lines of the parallelogram, then the area of the triangle will be half the area of the parallelogram. That is, area of a triangle = 1/2 area of a parallelogram if the triangle is on the same base and between the same parallel lines.
When all of the linear dimensions are doubled . . .-- the perimeter is also doubled-- the area is multiplied by 22 = 4.
It does not. The perimeter of a parallelogram is a characteristic of the parallelogram. The orientation: which side is considered a base makes do difference whatsoever.
The area of a Parallelogram is Base * Height The Perimeter is 2(side1 + side2)