The area and perimeter of a parallelogram are not sufficient to determine its dimensions.
area of parallelogram= base*height perimeter= 2(length+breadth)
Two sides of 8cm & two sides of 3cm fit the problem. 8+8+3+3=22cm (the perimeter you stated) AND a rectangle of 8x3cm is an area of 24cm2
The dimensions are 4 units by 15 units
p=2l+2w a=wl
No. In fact a parallelogram does not add up. It has a perimeter, it has an area, it has four angles and they are or can be added up. The the parallelogram itself cannot.
area of parallelogram= base*height perimeter= 2(length+breadth)
Two sides of 8cm & two sides of 3cm fit the problem. 8+8+3+3=22cm (the perimeter you stated) AND a rectangle of 8x3cm is an area of 24cm2
Nothing at all.
The dimensions are 4 units by 15 units
area is length times width
p=2l+2w a=wl
I smell a textbook question...
A square.
No. In fact a parallelogram does not add up. It has a perimeter, it has an area, it has four angles and they are or can be added up. The the parallelogram itself cannot.
I don't know about the relation in the perimeters of a triangle and a parallelogram but if a triangle is on the same base on which the parallelogram is and the triangle is between the same parallel lines of the parallelogram, then the area of the triangle will be half the area of the parallelogram. That is, area of a triangle = 1/2 area of a parallelogram if the triangle is on the same base and between the same parallel lines.
When all of the linear dimensions are doubled . . .-- the perimeter is also doubled-- the area is multiplied by 22 = 4.
28cm*22cm=616cm sq.