Want this question answered?
Assuming that the B term is the linear term, then as B increases, the graph with a positive coefficient for the squared term shifts down and to the left. This means that a graph with no real roots acquires real roots and then the smaller root approaches -B while the larger root approaches 0 so that the distance between the roots also approaches B. The minimum value decreases.
The real roots of what, exactly? If you mean a square trinomial, then: If the discriminant is positive, the polynomial has two real roots. If the discriminant is zero, the polynomial has one (double) real root. If the discriminant is negative, the polynomial has two complex roots (and of course no real roots). The discriminant is the term under the square root in the quadratic equation, in other words, b2 - 4ac.
It is the y-coordinate of the intercept (the x-coordinate being 0).
No, it is not.
the equation 6x^2 - 4x + 25 is a quadratic equation due to the 6x^2 term. Whatever number on the x squared term changes it to a quadratic equation if you were to get rid of the 6x^2 then the equation would simply be -4x+25 making it simply a linear equation. when ever you have an x raised to 2 that term is the quadratic term in the equation.
Assuming that the B term is the linear term, then as B increases, the graph with a positive coefficient for the squared term shifts down and to the left. This means that a graph with no real roots acquires real roots and then the smaller root approaches -B while the larger root approaches 0 so that the distance between the roots also approaches B. The minimum value decreases.
The real roots of what, exactly? If you mean a square trinomial, then: If the discriminant is positive, the polynomial has two real roots. If the discriminant is zero, the polynomial has one (double) real root. If the discriminant is negative, the polynomial has two complex roots (and of course no real roots). The discriminant is the term under the square root in the quadratic equation, in other words, b2 - 4ac.
It is the y-coordinate of the intercept (the x-coordinate being 0).
Yes; to have a quadratic function with two given roots, just decide what roots you want to have - call them "a" and "b" - and write your function as:y = (x - a) (x - b) You can multiply this out if you wish, to make it look like a standard quadratic function. Note that "a" and "b" can be any complex numbers. Graphing such a function is quite complicated; to graph both the x-value and the y-value, each of which is itself a complex (i.e., two-dimensional) number, you really need four dimensions.
In mathematics, a quadratic equation is a polynomial equation of the second degree. The general form is : where a≠ 0. (For if a = 0, the equation becomes a linear equation.) The letters a, b, and c are called coefficients: the quadratic coefficient a is the coefficient of x2, the linear coefficient b is the coefficient of x, and c is the constant coefficient, also called the free term or constant term. Quadratic equations are called quadratic because quadratus is Latin for "square"; in the leading term the variable is squared. A quadratic equation with real or complex coefficients has two (not necessarily distinct) solutions, called roots, which may or may not be real, given by the quadratic formula: : where the symbol "±" indicates that both : and are solutions.
No, it is not.
1st = The quadratic term. 2nd = The linear term. 3rd = The constant term.
Quadratic equations are called quadratic because quadratus is Latin for "square"; in the leading term the variable is squared.
kiki
It is x = +/- 2 depending on whether the second term in the equation is -12x or +12x.
the difference between the two is that in quadratic u find the factors of the last term that when u add/subtract u get the answer of the middle term. while the general quadratic trinomial u find the factors of both first term and last term and proceed to trial and error. Welcome -Delin-shaw Guillermo
the equation 6x^2 - 4x + 25 is a quadratic equation due to the 6x^2 term. Whatever number on the x squared term changes it to a quadratic equation if you were to get rid of the 6x^2 then the equation would simply be -4x+25 making it simply a linear equation. when ever you have an x raised to 2 that term is the quadratic term in the equation.