The real roots of what, exactly? If you mean a square trinomial, then:
If the discriminant is positive, the polynomial has two real roots.
If the discriminant is zero, the polynomial has one (double) real root.
If the discriminant is negative, the polynomial has two complex roots (and of course no real roots).
The discriminant is the term under the square root in the quadratic equation, in other words, b2 - 4ac.
There is no difference between real solutions and real roots.
Quadratics can two, one or no real roots.
There will be 2 real roots
The equation ax^2 + bx + c = 0 where a, b and c are real and a is non-zero has discriminant D = b^2 – 4ac. Then,if D > 0 the equation has two real roots which are distinct;if D = 0 the equation has two real roots which are coincident;if D < 0 the equation has two roots which form a complex conjugate pair (advanced mathematics only).
If you have a quadratic function with real coefficients then it can have: two distinct real roots, or a real double root (two coincidental roots), or no real roots. In the last case, it has two complex roots which are conjugates of one another.
real roots= Overdamped equal roots= critically damped complex roots /imaginary roots = Underdamped
There is no difference between real solutions and real roots.
It can tell you three things about the quadratic equation:- 1. That the equation has 2 equal roots when the discriminant is equal to zero. 2. That the equation has 2 distinctive roots when the discriminant is greater than zero. £. That the equation has no real roots when the discriminant is less than zero.
The real fourth roots are -0.3 and 0.3
Quadratics can two, one or no real roots.
There will be 2 real roots
The equation ax^2 + bx + c = 0 where a, b and c are real and a is non-zero has discriminant D = b^2 – 4ac. Then,if D > 0 the equation has two real roots which are distinct;if D = 0 the equation has two real roots which are coincident;if D < 0 the equation has two roots which form a complex conjugate pair (advanced mathematics only).
If you have a quadratic function with real coefficients then it can have: two distinct real roots, or a real double root (two coincidental roots), or no real roots. In the last case, it has two complex roots which are conjugates of one another.
They can be either. If they are roots of a real polynomial then purely imaginary would be symmetric and only real roots can be skew symmetric.
The short answer is "Nothing". In the complex domain, the number of nth roots of any real number is n. Every non-negative real number has 2 square roots. Every real number has 3 cube roots. Every non-negative real number has 2 real square roots and 2 imaginary ones. and so on. So what?
A quadratic equation can have a maximum of 2 solutions. If the discriminant (b2-4ac) turns out to be less than 0, the equation will have no real roots. If the Discriminant is equal to 0, it will have equal roots. But, if the discriminant turns out to be more than 0,then the equation will have unequal and real roots.
There are two roots, both real: -13 and +13