If 10 and 12 are the x and y coodinates then the straight line equation is:
y = 0.83x+3.7
If you mean a slope of 2/5 and the point (-15, 12) then equation is 5y = 2x+90
If the equation is y=12x, the slope is 12
what is the slope of the line that has the equation 4x+2y=12?
As a straight line equation: y = -3x+18 in slope intercept form
[ y = 12x ] is an equation, not a 'problem'. The graph of that equation is a straight line with a slope of 12 .
1 over -10.
-10
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
35
If you mean y = 12x then the slope of the line is 12
12
It is: y--5 = -3(x-4) => y = -3x+12-5 => y = -3x+7 in slope-intercept form