Points: (3, -6) and (-3, 0) Slope: -1 Equation: y = -x-3
Points: (3, 0) and (0, -9) Slope: 3 Equation: y = 3x-9
Slope: 5 Points: (-2, -3) Equation: y = 5x+7
y = -3x + 5
To find the equation in standard form of the line that contains points C and D, you first need the coordinates of those points. The standard form of a line is expressed as Ax + By = C, where A, B, and C are integers, and A should be non-negative. Using the coordinates of points C and D, you can calculate the slope and use the point-slope form to convert it to standard form. If you provide the coordinates of points C and D, I can help you derive the equation.
Choose the equation of the line that contains the points (1, -1) and (2, -2).
Points: (3, -6) and (-3, 0) Slope: -1 Equation: y = -x-3
Points: (3, 0) and (0, -9) Slope: 3 Equation: y = 3x-9
If you mean points of (-3, 2) and (5, -5) then the equation works out as 8y = -7x-5
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
Points: (1, 2) and (0, -2) Slope: 4 Equation: y = 4x-2
Points: (8, 10) and (-4, 2) Slope: 2/3 Equation: 3y = 2x+14
Slope: 5 Points: (-2, -3) Equation: y = 5x+7
y = -3x + 5
Slope: -5 Points: (6, 3) Equation: y = -5x+33
To find the equation in standard form of the line that contains points C and D, you first need the coordinates of those points. The standard form of a line is expressed as Ax + By = C, where A, B, and C are integers, and A should be non-negative. Using the coordinates of points C and D, you can calculate the slope and use the point-slope form to convert it to standard form. If you provide the coordinates of points C and D, I can help you derive the equation.
Points: (4, -4) and (-2, 0) Slope: -2/3 Equation: y = -2/3x-4/3 or as 3y = -2x-4