y = -3x + 5
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
To find the equation in standard form of the line that contains points C and D, you first need the coordinates of those points. The standard form of a line is expressed as Ax + By = C, where A, B, and C are integers, and A should be non-negative. Using the coordinates of points C and D, you can calculate the slope and use the point-slope form to convert it to standard form. If you provide the coordinates of points C and D, I can help you derive the equation.
Points: (-5, 9) and (-4, 7) Slope: -2 Equation: y = -2x-1 in slope intercept form
Equation of the straight line: y = -3/5x+2 in slope intercept form
The equations are equivalent.
y = 2x + 1.
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
To find the equation in standard form of the line that contains points C and D, you first need the coordinates of those points. The standard form of a line is expressed as Ax + By = C, where A, B, and C are integers, and A should be non-negative. Using the coordinates of points C and D, you can calculate the slope and use the point-slope form to convert it to standard form. If you provide the coordinates of points C and D, I can help you derive the equation.
Points: (8, 10) and (-4, 2) Slope: 2/3 Equation: 3y = 2x+14
Points: (-5, 9) and (-4, 7) Slope: -2 Equation: y = -2x-1 in slope intercept form
If you mean points of: (10, -2) and (20, -12) then it is a straigh line equation in the form of y = -x+8
Equation of the straight line: y = -3/5x+2 in slope intercept form
The equations are equivalent.
Points: (0, 5) and (5, 8)Slope: 3/5Equation: y = 3/5x+5 in slope intercept form
To determine the equation of the hypotenuse of triangle RST, you need the coordinates of points R, S, and T. Once you have these coordinates, you can calculate the slope of the line connecting the two points that form the hypotenuse. The equation can then be expressed in the slope-intercept form (y = mx + b) or point-slope form (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is a point on the line. Please provide the coordinates of points R, S, and T for a specific equation.
It is: y--3 = 6(x--1) => y = 6x+3 In standard form: 6x-y+3 = 0