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Q: What equation could be used to determine the area of a rectangle that is 4 cm wide and 10 cm long?

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area of the rectangle..

It could be the area formula for a rectangle which is: area = length times width

Same as a rectangle. It is, after all, a type of rectangle (lenght >< width)

The equation for a rectangle is h(height) x w(width) = area . By manipulating the equation we can show that width=area/length. So 132/12=11. This means the width of the rectangle is 11.

The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.

Because the equation of the area of a rectangle is Area=length*width When you multiply length by width, you are not only multiplying the numerical values, you are also multiplying the labels. A label multiplied by itself becomes squared, just like numbers multiplied by themselves. For example, the length of the rectangle could be 3 centimeters (cm) and the width could be 2 cm. To find the area, plug these into the equation: Area=3cm*2cm Area=(3*2)(cm*cm) Area=6 cm squared

The equation for the area of the rectangle is A = Y2 + 4 Y. A = L * W = (Y + 4) (Y)

Determining the area of a rectangle is simply multiplying its length by its width.

you must know the length of the rectangle as well in order to fill in the equation A=lengthxWidth

The equation for surface area of a square or rectangle is length times width. The equation for surface area of a triangle is base times height, divided by 2. The equation for surface area of a circle is pi times the square of the radius.

There is no "height" of a rectangle, unless it's a rectangular prism. Do you mean the length? If you have the area of the rectangle, the equation should be:A= L x WPlug in the area and the length and solve for the width, or plug in the area the width of the rectangle, and solve for the length.

2_x_ + 2(x – 4) = 45

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