For a fraction A/B, the fraction is improper if A > B. The reciprocal is B/A. So now A is the denominator, and B is the numerator, and B < A, so the reciprocal is a proper fraction. The answer would be always.
It is the reciprocal. A fraction, a/b is inverted to b/a
It isnt possible for it to b an improper fraction. For it to b an improper fraction, it has to first b a mixed no
It's the number on the bottom of the fraction.
To divide a fraction by itself is actually pretty easy. Let's say that we have a fraction which is a/b (so a and b could be any numbers and this could be any fraction). Then, we can do the following: (a/b)/(a/b) = (a/b)*(b/a) (in other words, when dividing by a fraction, you can do this by multiplying by the fraction flipped upside down) = (a*b)/(b*a) = 1 (because a and b cancel each other out) Therefore, any fraction (or indeed any number at all) divided by itself will give the answer of 1.
Suppose you have the improper fraction a/b where, since the fraction is improper, a > b.Divide a by b so that you have a quotient cand a remainder d.Then a/b = c d/b.
Suppose you have a fraction in the form a/b where a and b are integers and b > 0. Since the fraction is improper, a must be greater than b. Divide a ÷ b. Suppose b goes into a k times and leaves a remainder of r. Then a/b = k r/b
The mixed fraction a b/c = (ac + b)/c
When you multiply a nonzero fraction by its reciprocal you get 1. Take this example.Lets say you have a fraction called (a/b). The reciprocal of that fraction would be (b/a). If you multiply the two you'd get (a/b)*(b/a)=(ab/ab). Anything divided by itself is 1.
Suppose the parallel sides of the trapezium are a and b units where a < b. Then the fraction of the area of the trapezium that is the rhombus is a/[(a+b)/2] = 2a/(a+b).
If there is only the radical, sqrt(b), in the denominator, the form of the fraction is sqrt(b)/sqrt(b).If the denominator is of the form a + sqrt(b) then the form of the fraction is [a - sqrt(b)]/[a - sqrt(b)].It is also possible to use [-a + sqrt(b)]/[-a + sqrt(b)], and this form may be preferred is a^2 < b.