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What is the answer to 5x-3x plus x plus 8 equals 2x plus 1 plus x plus x?
5x-3x+x+8 = 2x+1+x+x 3x+8 = 4x+1 3x-4x = 1-8 -x = -7 x=7 Hope that helps.
Can you solve neg 4x minus1 minus 3x minus4 plus 5 equals neg 7x minus 1 minus 2x plus 1 plus 6?
-4x-1-3x-4+5 = -7x-1-2x+1+6 -7x = -9x+6 2x = 6 x = 3
What is the quotient and remainder when 12x4 -7x2 plus 1 is divided by 2x plus 1?
Fill in the missing powers of x in the dividend by having a coefficient of zero (0); then use long division: _________________ 6x³ - 3x² - 2x + 1 ________--------------------------------- 2x + 1 | 12x⁴ + 0x³ - 7x² + 0x + 1 _________ 12x⁴ + 6x³ _________ ------------- _______________ - 6x³ - 7x² _______________ - 6x³ - 3x² _______________ ------------- ____________________ - 4x² + 0x ____________________ - 4x² - 2x ____________________ ------------ ____________________________ 2x + 1 ____________________________ 2x + 1 ____________________________ -------- __________________________________0 ____________________________ ===== → (12x⁴ - 7x² + 1) ÷ (2x + 1) = 6x³ - 3x² - 2x + 1 with no remainder.
What is 4x-2x plus 1?
4x-1=2x+1
Can this be factored -4x-6x plus 2?
- 4X - 6X + 2 = 2(- 2X - 3X + 1) -------------------------that is all the factoring I can see to do here
What is the answer to 5x-3x plus x plus 8 equals 2x plus 1 plus x plus x?
5x-3x+x+8 = 2x+1+x+x 3x+8 = 4x+1 3x-4x = 1-8 -x = -7 x=7 Hope that helps.
What is the average of 2x plus 5 5x minus 6 and -4x plus 2?
(2x + 5) + (5x - 6) + (-4x + 2) = 3x + 1 There are three items so average = (3x + 1)/3 = x + 1/3
Can you solve neg 4x minus1 minus 3x minus4 plus 5 equals neg 7x minus 1 minus 2x plus 1 plus 6?
-4x-1-3x-4+5 = -7x-1-2x+1+6 -7x = -9x+6 2x = 6 x = 3
3x squared -5x plus 1 plus 8x squared - 2x -9?
(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
What is the quotient and remainder when 12x4 -7x2 plus 1 is divided by 2x plus 1?
Fill in the missing powers of x in the dividend by having a coefficient of zero (0); then use long division: _________________ 6x³ - 3x² - 2x + 1 ________--------------------------------- 2x + 1 | 12x⁴ + 0x³ - 7x² + 0x + 1 _________ 12x⁴ + 6x³ _________ ------------- _______________ - 6x³ - 7x² _______________ - 6x³ - 3x² _______________ ------------- ____________________ - 4x² + 0x ____________________ - 4x² - 2x ____________________ ------------ ____________________________ 2x + 1 ____________________________ 2x + 1 ____________________________ -------- __________________________________0 ____________________________ ===== → (12x⁴ - 7x² + 1) ÷ (2x + 1) = 6x³ - 3x² - 2x + 1 with no remainder.
What is 4x-2x plus 1?
4x-1=2x+1
What is 3x plus 2 x-1 plus 2x-4 x plus 2 equals 5?
Your notation is hard to read. Did you mean 3x+2x-1+2x-4x+2=5? You have a lot of weird spaces that make your x's look like multiplication or something. The first step is to get variables on one side of the equation and numbers on the other. Add 1 and subtract 2 from 5, giving 3x+2x+2x-4x=4 Now, simply do the math on the variables. 3x+2x+2x-4x giving you 7x-4x which equals 3x, so that means 3x=4(from our earlier work) divide both sides by 3, 3x/3=4/3 gives us x=4/3 or x=1 1/3 or x=1.3333333 however you like.
P 2x-9y q 5y plus 6-4x r 3x plus 3y-5 then p plus q plus r?
p + q + r = (2x - 9y) + (5y + 6 - 4x) + (3x + 3y - 5) = x - y + 1
Find the sum 3x2 plus 2x plus 3 plus x2 plus x plus 1?
3x2 + 2x + 3 + x2 + x + 1 = 4x 2+ 3x + 4
Can this be factored -4x-6x plus 2?
- 4X - 6X + 2 = 2(- 2X - 3X + 1) -------------------------that is all the factoring I can see to do here
How do you solve -3x plus 1 plus 4x plus 2-2x-14 plus 5x?
Start by putting like terms on each side, so the x values on one side and the numbers on the other side. The calcualte as appropriate to give one x value and one number value. -3x + 1 + 4x + 2 -2 x - 14 + 5 x -3x + 4x - 2x + 5x + 1 + 2 - 14 4x - 11
What are the points of contact of the following parabolas y equals 4x squared -2x -1 and y equals -2x squared plus 3x plus 5?
If: y = 4x^2 -2x -1 and y = -2x^2 +3x +5 Then: 4x^2 -2x -1 = -2x^2 +3x +5 Transposing terms: 6x^2 -5x -6 = 0 Factorizing: (3x+2)(2x-3) = 0 => x = -2/3 or x = 3/2 By substitution the points of contact are at: (-2/3, 19/9) and (3/2, 5)
