Your notation is hard to read. Did you mean 3x+2x-1+2x-4x+2=5?
You have a lot of weird spaces that make your x's look like multiplication or something.
The first step is to get variables on one side of the equation and numbers on the other. Add 1 and subtract 2 from 5, giving 3x+2x+2x-4x=4
Now, simply do the math on the variables. 3x+2x+2x-4x giving you 7x-4x which equals 3x,
so that means 3x=4(from our earlier work)
divide both sides by 3, 3x/3=4/3 gives us x=4/3 or x=1 1/3 or x=1.3333333 however you like.
it equals x1 it equals x1
2x2+7/x1
Let y = 3x y' = 3(x)' y' = 3(x1)' y' = 3[1x(1-1)] y' = 3(1x0) y' = 3(1 x 1) y' = 3 In general: y = xn y' nx(n-1)
Use the point-slope form: y - y1 = m(x - x1). From the givens, y1 = 2, x1 = 9, and m = -2. Thus, y - 2 = -2(x - 9) = -2x + 18, or y = -2x + 20.
inverse matrix. x1+x2+x3=3,000 -x1+5x2=0 2x1-3x3=0.
it equals x1 it equals x1
3
f(x1) = (-5)2 + 3*(-5) + 5.1 = 25 - 15 + 5.1 = 15.1 f(x2) = (6)2 + 3*(6) + 5.1 = 36 + 18 + 5.1 = 59.1 f(x2)-f(x1) = 59.1 - 15.1 = 44 x2 - x1 = 6 - (-5) = 11 So average rate of change = 44/11 = 4
Right, 3x-4x+9x-x1. 3x - x = 2x2. 9x-4x = 5x- 2x +5x = 7x
12 equals 3x(4) equals 6x(2) equals (12)x1
shut up and do your hw
y = 6*x1/2 - 3x dy/dx = 6*(1/2)*x-1/2 - 3 = 3x-1/2 - 3 = 3/sqrt(x) - 3 or 3[1/sqrt(x) - 1]
x²+6x+9=49 x²+6x-40=0 x1=-6/2 - Square root of ((6/2)²+40) x1=-3 - 7 x1= -10 x2=-6/2 + Square root of ((6/2)²+40) x2=-3 + 7 x2= 4
i think its pretty much the same thing because matrix X1 X2 IS ACTUALLY X1 X2
4
It is linear. The highest power is 1 (x = x1, y = y1) so it is linear.
3x-4y=40 (x=0) 3(0)-4y=40 -4y=40 y=40/-4 y=-10 x1 , y1 (13 , -10) (4y=0) 3x-4(0)=40 3x=40 x=40/3 x=13.33 or 13