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What is the exspression 16x2 - 128x plus 256 simplified?
16x2 - 128x + 256 = 16(x2 - 8x + 16) = 16(x - 4)2, or [4(x - 4)]2, or (4x - 16)2
How do you simplify 5x-6 plus 3x plus 12?
5x-6+3x+128x-6+128x+6
Find rational zero of the polynomial 3x4 plus 26x3 plus 91x2 plus 128x plus 52?
To be rational, the numerator has to be a factor of 52 (the last term), and the denominator has to be a factor of 3 (the coefficient of the first term). Try all the combinations, including negative numbers (52/1, -52/1, 52/3, -52/3, 26/1, 26/3, etc.), to see whether one of them is a zero.
How do you make the numbers 11-20 using four 4's?
11 = (42 - 4) - (4 / 4) 12 = (4 + 4) + (√4 + √4) 13 = (42 - 4) + (4 / 4) 14 = (4 + 4 + 4 + √4) 15 = (4 * 4) - (4 / 4) 16 = (4 + 4 + 4 + 4) 17 = (42 + √4) - (4 / 4) 18 = (42 + 4) - (4 - √4) 19 = (42 + 4) - (4 / 4) 20 = (4 * 4) + (√4 + √4)
How do you make the numbers 1-10 with four 4's using BODMAS?
Here is one set of solutions. The answers here are not unique. 1 = (4*4)/(4*4) 2 = 4/4 + 4/4 3 = (4+4+4)/4 4 = (4-4)*4 + 4 5 = (4*4 + 4) / 4 6 = 4 + (4+4)/4 7 = 4 + 4 - 4/4 8 = 4 + 4 + 4 - 4 9 = 4 + 4 + 4/4 10 = (44 - 4)/4
What is the exspression 16x2 - 128x plus 256 simplified?
16x2 - 128x + 256 = 16(x2 - 8x + 16) = 16(x - 4)2, or [4(x - 4)]2, or (4x - 16)2
How do you simplify 5x-6 plus 3x plus 12?
5x-6+3x+128x-6+128x+6
What is 20 percent of 128.00?
all you have to do is 128x.20 and u get 25.6
Is 8 gb the same as 1 tb?
No, 1TB is 1024GB, 128x larger than 8GB.
What is the gcf of 112x to the 9th power y to the 9th power 128x to the 2nd power y to the 7th power -80x to the 7th power y to the 2nd power?
112x9y9 128x2y7 -80x7y2 The GCF is 16x2y2
What are the coefficients of the binomial x plus 2 to the power of 6?
(x+2)6 (x2 + 4x + 4)(x+2)4 (x2 + 4x + 4)(x2 + 4x + 4)(x+2)2 (x2 + 4x + 4)(x2 + 4x + 4)(x2 + 4x + 4) (x4 + 4x3 + 4x2 + 4x3 + 16x2 + 16x + 4x2 + 16x + 16)(x2 + 4x + 4) (x4 + 8x3 + 24x2 + 32x + 16)(x2 + 4x + 4) (x6 + 4x5 + 4x4 + 8x5 + 32x4 + 32x3 + 24x4 + 96x3 + 96x2 + 32x3 + 128x2 +128x + 16x2 + 64x + 64) (x6 + 12x5 + 60x4 + 160x3 + 240x2 + 192x +64) the coefficeints are 1, 12, 60, 160, 240, and 192
What is the sum of three consecutive even integers if the sum of the first and third is 128?
The second integer is 64 (128/2), so the first is 62 and the third is 66.OrLet the 1st integer be x and the 3rd integer be y.Since even integers differ by 2, then we have:y = x + 4x + y = 128x + x + 4 = 1282x = 124x = 62So the integers are 62, 64, and 66, and their sum is 192
Find four consecutive integers such that the sum of the second and fourth is 132 show the work?
Let the first consecutive integer be x. So that:the second integer is x + 1,the third integer is x + 2, andthe fourth integer is x + 3.We have:(x + 1) + (x + 3) = 1322x + 4 = 1322x = 128x = 64 the first integerThus, the four consecutive integers are 64, 65, 66, and 67.
A right angled triangle has the length of its shorter sides as(2x+4) and (8x+8). if the length of hypotenuse is 10x, finds its area?
Remember for Right Angled Triangles. First using Pythagoras the area(A) of triangles is equal to half the base multiplied to the perpendicular height. side 'a' = 2x + 4 side b = 8x + 8 side h = 10x First using Pythagoras find the value of 'x' . Hence (10x)^2 = ( 2x + 4)^2 + ()8x + 8)^2 Hence 100x^2 = 4x^2 + 8x + 16 + 64x^2 + 128x + 64 Collect like terms and form a quadratic equation. 100x^2 - 4x^2 - 64x^2 -8x - 128x - 16 - 64 = 0 32x^2 - 136x - 80 = 0 Factor out '8' 4x^2 - 17x - 10 = 0 Use Quadratic Eq'n x = {--17 +/- sqrt[(-17)^2 - 4(4)(-10)]} / 2(4) x = {17 +/- sqrt[289 + 160]} / 8 x = {17 +/- sqrt[449]} / 8 x = {17 +/- 21.189....} / 8 x = 38.189... / 8 = 4.773.... & x = - 4.189 / 8 ; Unresolved because , philosophically you cannot have a negative length. Using 4.773... substitute for 'x' in to the two shorter sides. Hence A = (0.5)(2(4.773...) + 4)(8(4.773...) + 8) A = (0.5(9.547... + 4)(38.184... + 8) A = (0.5)(13.547...)(46.184...) A = 312.827.... units^2
Is there a minecraft texture pack that basically increases the resolution of the default to 32x or 64x I found minecraft enhanced but it was 128x to 256x?
If you go to minecraftforum.net, they have a thread dedicated to texture packs. The packs are sorted by resolution, so you can see if there's a 32x or 64x pack that has the right look and feel for you. I don't know of any texture packs that exactly mirror the original texture in a higher resolution. :(
Find rational zero of the polynomial 3x4 plus 26x3 plus 91x2 plus 128x plus 52?
To be rational, the numerator has to be a factor of 52 (the last term), and the denominator has to be a factor of 3 (the coefficient of the first term). Try all the combinations, including negative numbers (52/1, -52/1, 52/3, -52/3, 26/1, 26/3, etc.), to see whether one of them is a zero.
What is the greatest possible product that can be formed by two positive integers whose sum is 128?
That would be 64 x 64 = 4096 If you know calculus, this is a maxima-minima problem. X+ Y = 128 Y = 128 - X PRODUCT = P = XY = X ( 128 -X) = 128X - X^2 Take first derivative with respect to X and set = 0 - that is slope zero where value is either minimum or maximum dP/dX = 128 - 2X = 0 X = 64 Y = 64
