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What is the sum of three consecutive even integers if the sum of the first and third is 128?
Wiki User
∙ 13y ago
The second integer is 64 (128/2), so the first is 62 and the third is 66.
Or
Let the 1st integer be x and the 3rd integer be y.
Since even integers differ by 2, then we have:
y = x + 4
x + y = 128
x + x + 4 = 128
2x = 124
x = 62
So the integers are 62, 64, and 66, and their sum is 192
Wiki User
∙ 13y ago
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