54 = 625 (to find out sqr rt 625 then sqr rt again)
I'm asuming you meant "ten theta"the square of 5 is 2525 divided by 10 is 2.5so theta equals 2.5there you go =)
320 = 2x^2 + 12x 0 = 2x^2 +12x -320 Using the quadratic formula x = (-12 + sqr(144+4*2*320))/4 and x= (-12 - sqr(144+4*2*320))/4 x =( -12 + sqr(2560))/4 = 9.649 to 3 d.p. and x=(-12 - sqr(2560))/4 = -15.649 to 3 d.p
231 m2 is about 2,486.5 square feet.
sqr(-30) is i*sqr(30) We use i to represent the sqr(-1) because it is called an imaginary number. It takes an imagination to work with it. It is not fictitious.
The sin of 30 is sqr(3)/2 so 6 * sqr(30) is 6 * sqr(3)/2 this is also 6/2 * sqr(3) which simplifies to 3 * sqr(3) which is approximately 5.19615242
54 = 625 (to find out sqr rt 625 then sqr rt again)
You can't convert that.
I'm asuming you meant "ten theta"the square of 5 is 2525 divided by 10 is 2.5so theta equals 2.5there you go =)
x=5/2*sqr(3)
2x2-2x=12x2-2x-1=0a=2 b=-2 c=-1x= (-b +- sqr(b2-4ac))/2ax= (2 +- sqr(4 + 8))/4x= (2 +- sqr(12))/4x = 1/2 +- sqr(12)/4x ~= .5 +- 0.8660x ~=-0.3660 or x ~= 1.3660
320 = 2x^2 + 12x 0 = 2x^2 +12x -320 Using the quadratic formula x = (-12 + sqr(144+4*2*320))/4 and x= (-12 - sqr(144+4*2*320))/4 x =( -12 + sqr(2560))/4 = 9.649 to 3 d.p. and x=(-12 - sqr(2560))/4 = -15.649 to 3 d.p
Area is not measured in centimeter units. It may be guessed that the question should have indicated the area in square centimeters.The area of a regular pentagon is given as:A = s * s * sqr(25 + 10*(sqr(5)) / 4Solve for s:s = 2 * sqr (A / sqr(25 + 10*(sqr(5)))Insert the area of 600 square centimters:s = 2 * sqr (600 cm*cm / sqr(25 + 10*(sqr(5)))s = aproximately 19.67 cm
231 m2 is about 2,486.5 square feet.
sqr(-30) is i*sqr(30) We use i to represent the sqr(-1) because it is called an imaginary number. It takes an imagination to work with it. It is not fictitious.
x=81
110