There is some ambiguity in the question because of the absence of brackets. For example, is it 1/x + 3 ... or 1/(x+3) ... ?
So, this is my interpretation of the question. If it is not what you meant please resubmit using brackets.
1/(x+3) + 1/1/(x-3) = 1/(x+3) + (x - 3) = (1 + x2 - 9)/(x + 3) = (x2 - 8)/(x + 3)
== == Suppose f(x) = x3 + 3x2 - 2x + 7 divisor is x + 1 = x - (-1); so rem = f(-1) = 11
x3+3x2+6x+1 divided by x+1 Quotient: x2+2x+4 Remaider: -3
x3+3x2+3x+2 divided by x+2 equals x2+x+1
3
lim (x3 + x2 + 3x + 3) / (x4 + x3 + 2x + 2)x > -1From the cave of the ancient stone tablets, we cleared away several feet of cobwebs and unearthed"l'Hospital's" rule: If substitution of the limit results in ( 0/0 ), then the limit is equal to the(limit of the derivative of the numerator) divided by (limit of the derivative of the denominator).(3x2 + 2x + 3) / (4x3 + 3x2 + 2) evaluated at (x = -1) is:(3 - 2 + 3) / (-4 + 3 + 2) = 4 / 1 = 1
4
The inverse of a number is 1 divided by that number. So the inverse of x3 + 1 is 1/(x3 + 1).
2x2+7/x1
0.3333
== == Suppose f(x) = x3 + 3x2 - 2x + 7 divisor is x + 1 = x - (-1); so rem = f(-1) = 11
That depends on whether or not 2x is a plus or a minus
x3+3x2+6x+1 divided by x+1 Quotient: x2+2x+4 Remaider: -3
Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7
x3+3x2+3x+2 divided by x+2 equals x2+x+1
3
(x + 4) / (x3 - 11x + 20) = (x + 4) / (x2 + 4x - 5)(x + 4) = 1 / (x2 + 4x - 5) = 1 / (x + 5)(x - 1), where x ≠ -4
lim (x3 + x2 + 3x + 3) / (x4 + x3 + 2x + 2)x > -1From the cave of the ancient stone tablets, we cleared away several feet of cobwebs and unearthed"l'Hospital's" rule: If substitution of the limit results in ( 0/0 ), then the limit is equal to the(limit of the derivative of the numerator) divided by (limit of the derivative of the denominator).(3x2 + 2x + 3) / (4x3 + 3x2 + 2) evaluated at (x = -1) is:(3 - 2 + 3) / (-4 + 3 + 2) = 4 / 1 = 1