Ok this equation is 20 = 0.004 x N, yes? Rearrange for the variable 'N' to get 20/0.004 = N, N = 5000. Not hard.
1*20 = 20 Thus n = 20
Per cent or percentage equates to a hundredth. So, 7.75 = n x 20/100 n = 7.75 x 100/20 = 7.75 x 5 = 38.5. 20% of 38.5 is 7.75
There are 4845 combinations of 4 numbers from the set 1 - 20 nCr = n!/r!(n-r)! ⇒ 20C4 = 20!/4!(20-4)! = 20 x 19 x 18 x 17/4 x 3 x 2 x 1 = 4845
N x 5% = N/20.71000/20 = 3550.
Ok this equation is 20 = 0.004 x N, yes? Rearrange for the variable 'N' to get 20/0.004 = N, N = 5000. Not hard.
1*20 = 20 Thus n = 20
Try using a calculator! 20 x 4 = 80. It could not be simpler!
Per cent or percentage equates to a hundredth. So, 7.75 = n x 20/100 n = 7.75 x 100/20 = 7.75 x 5 = 38.5. 20% of 38.5 is 7.75
There are 4845 combinations of 4 numbers from the set 1 - 20 nCr = n!/r!(n-r)! ⇒ 20C4 = 20!/4!(20-4)! = 20 x 19 x 18 x 17/4 x 3 x 2 x 1 = 4845
k, l, m, and n are integers and k x l = 6, l x m = 20 m x n = 15 and k x n =9
Yes - 380 is the correct answer. Here is the formula: n x (n-1) or by multiplying out, n x n - n where 'n' is the number of teams. This formula applies to any league where each team plays every other team twice in a season. So for 20 teams in the English Premier League, the calculation is 20 x (20-1) = 20 x 19 = 380.
N x 5% = N/20.71000/20 = 3550.
20 diagonals For any n-sided polygon, the formula for the number of diagonals is (n/2) x (n-3), so for an octagon it is (8/2) x (8-3) = 4 x 5 = 20.
20 diagonals For any n-sides polygon, the formula for the number of diagonals is (n/2) x (n-3), so for an octagon it is (8/2) x (8-3) = 4 x 5 = 20.
N is between (4/3) and (5/3).
Let the unknown number be n.Then 20 x n = 177 : so n = 177 ÷ 20 = 8.85 or 817/20.