22z add 13z = 35
26
15z² - 22z - 5 = 0 → (5z + 1)(3z - 5) = 0
1977
I have a ring and it has a stap on it 13z what does that mean
13z-9
-6z + 2 = 3z + 4z + 28 Add 6z to both sides: 2 = 3z + 4z + 28 + 6z = 28 + 13z Subtract 28 from both sides: - 26 = 13z Divide both sides by 13: -2 = z
33z - 4 - 20z - 5 simplified would be 13z - 1.
If you mean: 33z-4-20z-5 then it is 13z-9 when simplified
2/16, 3/39, z/(13z) where z is any number, integer, non-integer, rational or irrational number.
Expand z plus 11 times z plus 11 = (z+11)(z+11) = z2 + 22z + 121.
If: 7x+11y+13z = 15 Then: 7(15/21)+11(15/33)+13(15/39) = 15 because 5+5+5 =15 So it follows: 7(15/21)*11(15/33)*13(15/39) = 125 because 5*5*5 = 125 Therefore: x = 15/21 y = 15/33 and z = 15/39 Or as: x = 5/7 y = 5/11 and z = 5/13
Solve by the substitution method the given system of the linear equations of 3 variables.2x + 7z = 648y + 6z = 403x - 2y + 4z = 46 (add the first equation with the second equation)2x + 8y + 13z = 1043x - 2y + 4z = 46 (multiply the second equation by 4)2x + 8y + 13z = 10412x - 8y + 16z = 184 (add both equations)14x + 29z = 28814x + 29z = 2882x + 7z = 64 (multiply the second equation by -7)14x + 29z = 288-14x - 49z = -448 (add both equations)-20z = -160 (divide both sides by -20)z = 82x + 7z = 64 (substitute 8 for z)2x + 7(8) = 642x + 56 = 64 (subtract 56 to both sides)2x = 8(divide by 2 to both sides)x = 48y + 6z = 40 (substitute 8 for z)8y + 6(8) = 408y + 48 = 40 (subtract 48 to both sides)8y = -8 (divide by 8 to both sides)y= -1Thus, the solutions are x = 4, y = -1, and z = 8.