Q: How do you factor completely x3 27y3?

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x3+27y3 = (x+3y) · (x2-3xy+9y2)

(3y - 1)(9y2 + 3y + 1)

x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)

(x + 2)(x ^2 + 1)

x(x + 3)(x - 4)

(x - y)(x^2 + xy + y^2

x3-343

(x-2)(x+1)(x+5)

x(x+3)(x+5)

(x + 1)(x - 2)(x + 5)

Since x3 is a factor of x5, it is automatically the GCF.

Greatest common factor of x4 and x3 is x3.

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How do you factor completely x3 27y3?