22
sqrt(a2 + a2) = sqrt(2a2) = sqrt(2)*sqrt(a2) = sqrt(2)*asqrt(a2 + a2) = sqrt(2a2) = sqrt(2)*sqrt(a2) = sqrt(2)*asqrt(a2 + a2) = sqrt(2a2) = sqrt(2)*sqrt(a2) = sqrt(2)*asqrt(a2 + a2) = sqrt(2a2) = sqrt(2)*sqrt(a2) = sqrt(2)*a
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
a3 - 2a2 + 4a - 8 = a2(a - 2) + 4(a - 2) = (a - 2)(a2 + 4)
(a2 + 2)(b + 3)
No. If you expand (a + b)2 you get a2 + 2ab + b2. This is not equal to a2 + b2
a3 + b3 + c3 + 2(a2)b + 2(b2)c + 2(a2)c + 2ab2 + 2(c2)b +abc
int x = 2 * (a + b);
( a2 ) ( a2+1 )
(a2 + a + a2) = (2a2 + a) = a (2a + 1)
a2/2
a2+30a+56=0 , solve for a Using the quadratic formula, you will find that: a=-2 , a=-28
(a2 + 5a + 6)/(a - 2) = (a + 2)*(a 3)/(a - 2) which cannot be simplified further. It can, however be written as (a2 - 2a + 7a - 14 + 20)/(a - 2) which is (a + 7) + 20/(a - 2)