First you can factor a^2 from the first two terms and 4 from the last two terms. (a^2)(a-2)+4(a-2) You can see that they both have (a-2) as a factor. So it is (a^2+4)(a-2)
8
5a - 10 = 4a + 8 is a linear equation in one variable.
a=-12
4*4+8 = 24
(a - 2)(a^2 + 4)
First you can factor a^2 from the first two terms and 4 from the last two terms. (a^2)(a-2)+4(a-2) You can see that they both have (a-2) as a factor. So it is (a^2+4)(a-2)
2a*3 = 8+4a 6a = 8+4a 6a-4a = 8 2a = 8 a = 4
8
5a - 10 = 4a + 8 is a linear equation in one variable.
It can do, for the right value of A
Solve the following equation for A : 2A/3 = 8 + 4A
a=-12
4*4+8 = 24
2a2+33a+136 = (2a+17)(a+8) when factored
a=8 -5+4x8=27
8